x^2-61x-128=0

Solution for x^2-61x-128=0 equation:

x^2-61x-128=0

a = 1; b = -61; c = -128;
Δ = b2-4ac
Δ = -612-4·1·(-128)
Δ = 4233
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-\sqrt{4233}}{2*1}=\frac{61-\sqrt{4233}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+\sqrt{4233}}{2*1}=\frac{61+\sqrt{4233}}{2}
$